Precession in a central potential

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Homework Help Overview

The discussion revolves around the concept of precession in a central potential, specifically focusing on the parametrization of an orbit in polar coordinates. Participants are examining the shift in the angular position of the periapsis after one complete orbit.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive the shift in angular position using a given parametrization. There are discussions about the periodicity of the trajectory and how it relates to the shift in angle, with some questioning the necessity of the exact trajectory for the solution.

Discussion Status

There are multiple interpretations being explored regarding the shift in angular position, with some participants suggesting different expressions for the shift. The conversation reflects a mix of agreement and differing viewpoints on the approach to the problem.

Contextual Notes

Participants are considering the implications of the parameter \Gamma on the periodicity of the trajectory, with specific values leading to different conclusions about the shift in periapsis. There is an underlying assumption about the nature of the orbit and its periodicity that is being examined.

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Homework Statement



Consider the following parametrization of an orbit in polar form,

\ell u = 1 + e \cos[(\phi -\phi_0)\Gamma]

where u = 1/r.

I'm trying to find the shift in the angular position of the periapsis after one complete orbit.

The Attempt at a Solution



Choose axes so that the point of first closest approach is \phi_0.

u'(\phi) = - \Gamma e \sin[(\phi -\phi_0)\Gamma]

Setting u'(0) =0 we obtain

(\phi -\phi_0)\Gamma = n \pi where n is an integer.

So after one complete orbit I guess the shift is \Delta \phi = \phi - \phi_0 = \frac{\pi}{\Gamma}, or should that be \frac{2pi}{\Gamma}?

Thanks.
 
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I preffer this:

\frac{2pi}{\Gamma}-\frac{2pi}{1}

To solve this problem, you even don't need to consider the exact trajectory.
You simply need to check how much (an angle) the trajectory deviates from periodicity.
For \Gamma = 1 the trajectory is periodic and there is no shift.
 
How did you obtain 2Pi/Gamma - 2Pi?
 
On reflection I get 2\pi/\Gamma. I think the first perihelion occurs at 0, the first aphelion occurs at \pi/\Gamma and the second perihelion at 2\pi/\Gamma.
 

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