Predicting Precipitates: A Double Displacement Homework Exercise

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The discussion focuses on predicting the formation of precipitates in double displacement reactions. The first combination, barium hydroxide and ammonium phosphate, produces barium phosphate as a solid precipitate. The second combination, silver nitrate and potassium acetate, results in silver acetate precipitating out. The third combination, copper(I) sulfate and sodium chloride, yields copper(I) chloride as a solid. Overall, the homework attempts correctly identify the precipitates formed in each reaction.
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Homework Statement



Which of the following combinations of compounds will produce a precipitate?

1. Barium hydroxide and ammonium phosphate
2. Silver nitrate and potassium acetate
3. Copper(I) sulfate and sodium chloride

Homework Equations



Double displacement.

The Attempt at a Solution



1. ##3(Ba(OH)_2 )_{aq} + 2((NH_4)_3 PO_4)_{aq} → Ba_3((PO_4 )_2)_{s} + 6(NH_4 OH)_{aq}##

The solid precipitate formed will be barium phosphate.

2. This one I'm a bit unsure about because of the potassium acetate.

##(AgNO_3)_{aq} + (KC_2H_3O_2)_{aq} → (AgC_2H_3O_2)_{s} + (KNO_3)_{aq}##

The solid precipitate formed will be silver acetate.

3. ##(Cu_2SO_4)_{aq} + 2(NaCl)_{aq} → 2(CuCl)_{s} + (Na_2SO_4)_{aq}##

The sold precipitate formed will be copper(I) chloride.

Do these look okay? I want to make sure I'm doing these properly.
 
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