Predicting spin and parity of excited states from shell mode

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SUMMARY

This discussion focuses on predicting the spin and parity of excited states for fluorine (F, A=17, Z=9) using the shell model. The ground state configuration is established as J^P = (5/2)^+. For the first excited state, promoting a proton from the (1p 1/2) level leads to ambiguity in determining J^P based on whether the spin and parity derive from the hole or the new filled level. The second excited state involves promoting a neutron from the (1p 1/2) level, resulting in multiple possible J^P values depending on the same considerations. The conclusion emphasizes that unpaired nucleons contribute to the spin and parity, and the shell model's reliability diminishes with three or more unpaired nucleons.

PREREQUISITES
  • Understanding of the shell model in nuclear physics
  • Familiarity with nuclear spin and parity concepts
  • Knowledge of nucleon configurations and their implications
  • Basic grasp of unpaired nucleons and their effects on nuclear states
NEXT STEPS
  • Study the shell model's application in predicting nuclear properties
  • Research the implications of unpaired nucleons on nuclear spin and parity
  • Learn about the Nordheim rules and their relevance to nuclear structure
  • Explore advanced topics in nuclear shell filling order and energy levels
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Nuclear physicists, students studying nuclear structure, and researchers interested in the shell model and its applications in predicting nuclear properties.

pondzo
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Homework Statement

Consider the following example from a previous exam. We are to predict the spin and parity for F(A=17,Z=9), Florine, in the ground state and the first two excited states using the shell model.

Ground state:
Neutrons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^2

Protons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^2 (1d 5/2)^1

Thus J^P = (5/2)^+

First excited state: Promote one proton from the (1p 1/2) level
Neutrons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^2

Protons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^1 (1d 5/2)^2

Does the spin and parity come from (a) the hole created or (b) the new filled level. If (a) then J^P = (1/2)^-. If (b) then J^P = (0)^+.
Second excited state: Promote one neutron from the (1p 1/2) level
Neutrons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^1 (1d 5/2)^1

Protons: (1s 1/2)^2 (1p 3/2)^4 (1p 1/2)^2 (1d 5/2)^1

Does the spin and parity come from (a) the hole created or (b) the new filled level. If (a) then the possible J values range from |1/2 - 5/2| to (1/2 + 5/2) in steps of one, so J=2 or 3. The parity multiplies so we have a minus from the l=1 neutron and a positive from the l=2 proton thus parity is minus and J^P = (2)^- or (3)^-. If (b) then J ranges from |5/2 - 5/2| to (5/2 + 5/2) in steps of one so J = 0,1,2,3,4 or 5. The parities both come from the same l level (d) so is positive. Thus J^P = (0)^+, (1)^+, (2)^+, (3)^+, (4)^+ or (5)^+.

So how do we get the spin's and parities from the excited states? Is it determined by the hole created or the new excited level?

Also how do I know which would be the first excited level and which would be the second? And is there a way to figure out which levels get filled up first when calculating the ground state, or should I just remember the order of the levels?

We are not expected to know the Nordheim rules.
 
I have come to the conclusion that any unpaired nucleons will contribute to the spin/parity, not just the ones from the hole created or the new level filled. And if it so happens that an excited state yields three or more unpaired nucleons, then the shell model is no longer reliable in predicting the spin and parity of the nucleus.
 

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