PreExam Problems: Understanding Series Nature & Convergence Radius

  • Thread starter Thread starter csi86
  • Start date Start date
csi86
Messages
7
Reaction score
0
There are some problems my lecturer gave me which I can't solve ,or I am very unsure about my approach :

1. Study the nature of this series : \sum_{n=1}^\infty \frac{a^{n}}{n^{2}}

2. Expand as a series of powers of x the function f(x)= ln{(1+x)} + \frac {1}{1-x} + e^{2x} and determine the convergence radius of the resulting one.I know that the last one is done using the Taylor but I ain't sure about my approach, some hints pls.

Thank you for your time.
 
Last edited:
Physics news on Phys.org
For the first one, do the terms get larger or smaller as n increases?

For the second one, what is your approach that you're not sure about?
 
Sorry I have an error in the latex code on the first one.

@Office_Shredder : Depends on the value of a :
if it is in (-1,1) then the terms become smaller,
if if is in {-1,1} then they also become smaller,
else they become larger, as n increases.On the secound one, I know some Taylor expansions as I searched for them on wikipedia, and I know the e^{x} expansion, as I have to get e^2x I think I will multiply that expansion by itself...
 
Sorry about my Latex problems... I have now finally fixed them. :D
 
1. \sum_{n=1}^\infty \frac{a^{n}}{n^{2}}

\lim_{n\rightarrow \infty} \frac{a^{n}}{n^{2}}\times n = \frac{a^{n}}{n} = \infty (assuming a > 1) So it converges at 1 and diverges for all other x.
2. f(x)= \ln{(1+x)} + \frac {1}{1-x} + e^{2x}

\ln{(1+x)} = \int \frac{1}{1+x}
 
Last edited:
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Replies
3
Views
1K
Replies
5
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
1
Views
1K
Replies
6
Views
2K
Replies
10
Views
1K
Back
Top