Prefactor of classical electron radius

Click For Summary
SUMMARY

The discussion centers on the derivation of the classical electron radius by equating the energy of the electric field with mec², considering the electron as a sphere of finite extent. It highlights the significance of prefactors (3/5 or 1/2) that arise from different charge distributions, such as constant charge density and constant surface density. The conversation questions the rationale behind ignoring these prefactors while retaining the factor of 4 in the denominator, attributing the latter to physical constants rather than geometric assumptions.

PREREQUISITES
  • Understanding of classical electromagnetism
  • Familiarity with the concept of energy density in electric fields
  • Knowledge of charge distribution models
  • Basic principles of relativistic energy-mass equivalence (E=mc²)
NEXT STEPS
  • Research the derivation of the classical electron radius in detail
  • Explore the implications of different charge distribution models on physical calculations
  • Study the role of prefactors in physical equations and their significance
  • Investigate the relationship between physical constants and geometric assumptions in theoretical physics
USEFUL FOR

The discussion is beneficial for physicists, particularly those specializing in electromagnetism and theoretical physics, as well as students seeking to deepen their understanding of the classical electron radius and its derivation.

greypilgrim
Messages
583
Reaction score
44
Hi,

Assuming the electron is a sphere of finite extent, the classical electron radius is derived by equating the energy of the electric field with mec2. For the computation of the field energy, we have to assume a charge distribution. Both constant charge density and constant surface density lead to prefactors (3/5 or 1/2) which are somehow just ignored.

Why? If we are only interested in the order of magnitude, why drop these prefactors but keep 1/4?
 
Physics news on Phys.org
I think it's just for "vague ballpark" calculation, yeah, since the prefactor depends on rather arbitrary assumptions (charges are on surface, or equally distributed). Regarding the factor 4 in the denominator, that one is likely left in there because it comes from the other physical constants, not the geometrical assumptions.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
509
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K