Preparation of alkenes from alcohols

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The discussion focuses on the preparation of alkenes from alcohols, specifically pentenes and their corresponding alcohols. Two primary reactions are highlighted: the conversion of CH3-CHOH-CH2-CH2-CH3 and CH2OH-CH2-CH2-CH2-CH3 to their respective alkenes in the presence of acid and heat. Cyclopentanol is also mentioned as a precursor for Cyclopentene. Participants note the existence of branched pentenes and the need for clarity regarding the inclusion of isomers. The conversation emphasizes that multiple precursor alcohols can lead to the same alkene, indicating a variety of possible structures.
ChemDoodle
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Q. Draw the structure for all possible alkenes & the alcohols from which they can be prepared.

CH3-CH=CH-CH2-CH3 <---- CH3-CHOH-CH2-CH2-CH3

CH2=CH-CH2-CH2-CH3 <---- CH2OH-CH2-CH2-CH2-CH3

Both in the presence of H+ & heat.

I also drew Cyclopentanol from which we can prepare Cyclopentene.

Are these all the possible pentenes? And are these equations correct?

Thankyou (:
 
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I suppose they need to have 5 C atoms , as if not the possibilities would be cosmological :P.
 
There is a third pentanol which you have not included.

There are also branched pentenes - but whether they count may depend on the exact wording of the question.

Plus zillions of compounds with other number of carbons :wink:

--
methods
 
Lok said:
I suppose they need to have 5 C atoms , as if not the possibilities would be cosmological :P.
Haha Yeaa..I meant pentenes not alkenes :P :$
 
ChemDoodle said:
Q. Draw the structure for all possible alkenes & the alcohols from which they can be prepared.

CH3-CH=CH-CH2-CH3 <---- CH3-CHOH-CH2-CH2-CH3

CH2=CH-CH2-CH2-CH3 <---- CH2OH-CH2-CH2-CH2-CH3

Both in the presence of H+ & heat.

I also drew Cyclopentanol from which we can prepare Cyclopentene.

Are these all the possible pentenes? And are these equations correct?

Thankyou (:

Good so far, but incomplete. For example you can get to CH2=CH-CH2-CH2-CH3 from two precursor alcohols (and you have written them both) and you can get to CH3-CH=CH-CH2-CH3 from two precursor alcohols, one of which you have shown and one is not shown.

And of course there are the isomers that Borek mentioned as well.
 

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