Preparing Aqueous Solutions for Chemistry Students

AI Thread Summary
To prepare the aqueous solutions, first, calculate the mass of ethanol needed for the 0.0515 m solution by using the formula for molality, which involves the mass of the solvent (water). For the HCl solution, determine the mass of the 35.3% HCl required by applying the mass percentage formula to achieve the desired final mass and concentration. The discussions highlight the need for clarity in the steps involved in these calculations, emphasizing the importance of understanding molality and mass percentage concepts. Participants are encouraged to share their methodologies and any relevant equations to assist in solving these problems. Clear guidance on these preparation methods is essential for chemistry students.
jdhutto
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Chem problem need help...

Homework Statement



How would you prepare the following aqueous solutions?
(a) 1.10 kg of 0.0515 m ethanol (C2H5OH) from ethanol and water
Add___ g C2H5OH to ____ g H2O.

(b) 511 g of 15.0 mass % HCl from 35.3 mass % HCl
Add___ g of 35.3% HCl to ___ g of water.



Homework Equations





The Attempt at a Solution



Im not sure what to do here...somebody please tell me the steps
 
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Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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