Pressure Amplitude to Pa: 1E-7 atm Conversion

AI Thread Summary
To convert a pressure amplitude of 1E-7 atm to pascals (Pa), use the conversion factor of 101325 Pa per atm. Multiplying 1E-7 by 101325 results in a pressure amplitude of 10.1325 Pa. It's crucial to include the correct units in calculations for accuracy. This conversion is essential for precise measurements in various scientific applications. Accurate pressure unit conversions facilitate better understanding and communication in technical fields.
cseet
Messages
40
Reaction score
0
Hi all,

Pls kindly advise how do I convert Pressure Amplitude of 1E-7 atm to the correct pressure unit (Pa - pascal)?

much appreciated
cseet
 
Physics news on Phys.org
1 atmosphere = 101300 Pa
 


Hi cseet,

To convert pressure amplitude from atm to Pa, you can use the conversion factor of 101325 Pa/atm. So, to convert 1E-7 atm to Pa, you would multiply 1E-7 by 101325. This would give you a pressure amplitude of 10.1325 Pa. Remember to always include the correct units in your calculations to ensure accuracy.

I hope this helps! Let me know if you have any further questions.

 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top