Pressure at a centroi thermo fluids

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SUMMARY

The discussion focuses on calculating the pressure at the centroid of a liquid surface, specifically using water with a density of 1,000 kg/m³. The user applied the formula for pressure, where pressure (y) equals depth (l) multiplied by the density (e), resulting in a pressure of 50,000 N/m² at a depth of 5 meters. Subsequently, the force acting on the plate was calculated by multiplying this pressure by the area, yielding a total force of 250 kN. The calculations are correct based on the provided parameters.

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donniemateno
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ive got this q in my homework calculate the pressure at the centroid and hence the force acting plate. the surface is free liquid is water.
ive using a formula l x e = y
l being length or depth in this case
e being value of water which i found to be 1 x 10 to power of 3 kg/m3
y being the pressure at the centroid


so in my case that's 5 x 1x10powerof 3= 50000n/m2

the to work out force on the plate I've used
pressure x area

so 50000 x 5 = 250Kn

have i gone horribly wrong?? doesn't seem right to me
 
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