Pressure drop w.r.to time through a orifice dia(D) in a container of volume (V)

AI Thread Summary
The discussion focuses on calculating the time required for the pressure in a container with an initial pressure of 10 bar and a volume of 100,000 cubic cm to drop to 5 bar. Key considerations include whether the substance in the container is a gas or liquid, and if it behaves as an ideal gas while escaping against atmospheric pressure of 1 bar. The user presents a mathematical approach involving adiabatic expansion and conservation of energy to model the pressure drop over time. The equations derived involve variables such as outlet area, exit velocity, and mass remaining in the tank. The user acknowledges potential errors in their calculations and expresses intent to refine their approach.
Jothiram80
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Let initial preasure (P) = 10 bar,volume of container (V)=100000 cubic cm.
At what time period pressure will become 5 bar.
 
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Jothiram80 said:
Let initial preasure (P) = 10 bar,volume of container (V)=100000 cubic cm.
At what time period pressure will become 5 bar.
What kind of a substance is in the container? A gas or a liquid? If it is a gas, is it an ideal gas? Is it escaping against atmospheric pressure of 1 bar?

AM
 
I make no guarantees for the correctness of this, but here's what I got.
Let vol of tank be V, pressure P(t), mass remaining in tank m(t), outlet area A, exit velocity f(t).
In time dt, a volume A*f.dt, mass (Afm/V).dt, exits.
Assuming adiabatic expansion:
P(t+dt)(V+Af.dt)γ = P(t)Vγ, where γ = 1.4
whence
P' = -PγAf/V
m' = -fAm/V
By conservation of energy
(P-Pa)Af.dt = Af3m.dt/2V
where Pa is ambient pressure.
I forgot about Pa at first, and obtained
(γ-1)At = ((P0/P)(1-γ)/2γ - 1)√(2Vm0/P0)
where P0 = P(0), m0 = m(0).
I might try to correct that tomorrow.
 
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