Pressure in liquid

  • Thread starter mr.book
  • Start date
  • #1
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This started to bother me today. In the first picture, there's a cup wheres a certain amount of water in it. A ball made of aluminium hasnt been dropped in the cup yet.
In the second picture, the ball has been dropped in.

The ball has not sinked, a string is holding it.

Now please tell me, how did the pressure on the botton of the cup created BY THE WATER change?
I mean, the water level just rose. So the pressure should also.
But there seems to be another solution to the problem, and I just cant figure it out.

The equation for liquid pressure is p= RO*g*h.

Thanks in advance,






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[PLAIN]http://www.cornerpocketpool.com/images/catalog/category57.jpg [Broken]
http://www.billiardlover.com/mcdermott-pool-cue.html [Broken]
 
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Answers and Replies

  • #2
cjl
Science Advisor
1,917
486
Your initial solution is correct. Since the depth of the water is now larger, the pressure at the bottom is higher.
 

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