Pressure of balls bouncing on area

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Homework Help Overview

The problem involves calculating the average pressure exerted by multiple balls bouncing on a surface area. It is situated within the context of mechanics, specifically focusing on concepts of pressure, force, and momentum.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate pressure using various methods but struggles to arrive at the expected answer. Some participants discuss the relationship between pressure, force, and momentum, suggesting that the change in momentum of the balls is crucial for the calculation.

Discussion Status

Participants are actively engaging with the problem, with one offering a formula for pressure and another detailing their calculations. There is a recognition of potential errors in the original poster's approach, particularly regarding the sign of momentum, indicating a productive direction in the discussion.

Contextual Notes

The original poster has attempted multiple calculations and is working under the constraints of a homework assignment, which may impose specific methods or approaches to be used.

LoN
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a 5g balls fall dropped from 3m bounces up 1m. if 100 such balls fall on an area of 2m^2 every second what is the average pressure exerted by the balls?

ive tried to solve this problem 100 different ways and i can't get the answer (3Pa).
 
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LoN, you wouldn't happen to have a Physics 213 midterm tonight at 7pm, would you? ;)

Pressure is force/area and force is (change in momentum)/time. You're provided with the area and time, so all you have to find is the change in momentum of the ball as it hits the surface.
 
haha yes i do. small world eh :biggrin:

i must not be setting this up right, here's what I am doing.

1/2 m v^2 = mgh solve for v for each height, 1 m and 3m.

then find the change in momentum by multiplying the vs i have solved for by the mass of the ball and subtract. i get .0162 for the change in momentum. so then i multiply that by 100(?) and divide by 2m^2 and i end up with .81Pa

where am i screwing up :confused:
 
Remember that the momentum as the ball is going down is negative, and the momentum as the ball is going up is positive.

Good luck tonight!
 
thanks for the help, what a lame mistake i was making
 

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