# Pressure of fluid in container

1. Sep 18, 2007

### faoltaem

1. The problem statement, all variables and given/known data

A cylindrical container with a cross sectional area of 65.2 cm$$^{2}$$ holds a fluid of density 806kg/m$$^{3}$$. At the bottom of the container the pressure is 116 kPa
a) What is the depth of the fluid?
b) Find the pressure at the bottom of the container after an additional 2.05 $$\times$$ 10$$^{-3}$$ m$$^{3}$$ of this fluid is added to the container. Assume no fluid spills out of the container.

2. Relevant equations

3. The attempt at a solution

a) A = 65.2 cm$$^{2}$$
$$\rho$$ = 806 kg/m$$^{3}$$
P(bottom) = 116 kPa = 1.16 $$\times$$ 10$$^{5}$$ Pa

closed manometer $$\rightarrow$$ P = $$\rho$$gh

h = $$\frac{P}{\rhog}$$ = $$\frac{1.16 \times 10^{5}}{806 \times 9.81}$$
= 14.67 m

2. Sep 18, 2007

### faoltaem

sorry i didn't mean to finish it yet there is a later post with more in it