Prime divides its binomial coefficient?

obo
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Hi all, this homework problem's been driving me nuts. It seems like it's probably pretty straightforward and I'm missing something obvious, but I just can't work it out.

Homework Statement



prove that if p is a prime number that p|B(p,m) where B(p,m) is the ordinary binomial coefficient (i.e. p Choose m) for 0 < m < p

Homework Equations



B(p,m) = p!/m!(p-m)!

The Attempt at a Solution



If you factor p out of the binomial coefficient, you're left with (p-1)!/m!(p-m)!, which must be an integer. Thus I need to be able to show that m!(p-m)!|(p-1)! somehow. I've monkeyed around with the expressions to try and recover a multiple of a binomial coefficient or something, but haven't been able to... but I'm getting the feeling that I'm taking the wrong approach here =/

Any hints here would be very much appreciated!

Cheers
 
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can you show p divides (p,1)?

how about using that result to consider (p,2)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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