gnome
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In the Davis, Sigal & Weyuker textbook "Computability, Complexity and Languages" their proof that f(x) = x + y goes like this:
\begin{equation*}\begin{split}f(x,0) &= u_1^1(x)\\f(x,y+1) &= g(y,f(x,y),x)\end{split}\end{equation*}
where g(x_1,x_2,x_3) = s(u_2^3(x_1,x_2,x_3)).
And (I'm paraphrasing now in the interest of brevity) these functions u, s and g are all primitive recursive so therefore f is too.
I'm wondering, would it be equally valid (and simpler) to say
\begin{equation*}\begin{split}f(x,0) &= u_1^1(x)\\f(x,y+1) &= s(f(x,y))\end{split}\end{equation*}
followed by the same explanation?
Apparently, the reason for the form of their proof is that they defined recursion to be one of these two "things":
So I guess my question boils down to, is that just their definition of recursion, or is it everybody's?
i.e. does every proof involving recursion have to be in exactly that format?
\begin{equation*}\begin{split}f(x,0) &= u_1^1(x)\\f(x,y+1) &= g(y,f(x,y),x)\end{split}\end{equation*}
where g(x_1,x_2,x_3) = s(u_2^3(x_1,x_2,x_3)).
And (I'm paraphrasing now in the interest of brevity) these functions u, s and g are all primitive recursive so therefore f is too.
I'm wondering, would it be equally valid (and simpler) to say
\begin{equation*}\begin{split}f(x,0) &= u_1^1(x)\\f(x,y+1) &= s(f(x,y))\end{split}\end{equation*}
followed by the same explanation?
Apparently, the reason for the form of their proof is that they defined recursion to be one of these two "things":
and they had to put their proof into the same form as their definition of recursion.Either:
\begin{equation*}\begin{split}h(0) &= k\\h(t+1) &= g(t,h(t))\end{split}\end{equation*}
or:
\begin{equation*}\begin{split}h(x_1,...,x_n,0) &= f(x_1,...,x_n),\\h(x_1,...,x_n,t+1) &= g(t,h(x_1,...,x_n,t),x_1,...,x_n)\end{split}\end{equation*}
So I guess my question boils down to, is that just their definition of recursion, or is it everybody's?
i.e. does every proof involving recursion have to be in exactly that format?