The attached image is a graph showing the strength of the electric and magnetic fields associated with a classical electromagnetic wave at different places at the same time. It has nothing to do with photons (which, as mfb says, don't have a path).Daniel Petka said:The path of a photon is a perfect straight line not a sine wave, right? (if the probability amplitude is zero)
This is interpretation dependent statement.mfb said:A photon does not have a path.
Daniel Petka said:If a photon doesn't have any path, how can it then interact with let's say only electrons in front of him? Common sense tells me that light must have a path.
Light has a path, but that doesn't mean a photon does. A beam of light is not a stream of photons flowing by the way a river is a stream of water molecules flowing by.Daniel Petka said:Common sense tells me that light must have a path.
They are indeed... much of the problem comes from the word "particle", which as used in quantum physics doesn't mean at all what you'd expect from the common English-language meaning of the word. Photons are especially complicated because they have no rest mass, so cannot be treated using "ordinary" non-relativistic quantum mechanics, the stuff you study in your first few undergraduate years.Daniel Petka said:Ok... photons are strange [emoji23]
Are you referring to the polarisation here?Daniel Petka said:OK but please don't tell me that photons don't have a 3 dimensional orientation.
I think the polarization angle lies in the plane orthogonal to the momentum. Which is only one degree of freedom.Daniel Petka said:OK but please don't tell me that photons don't have a 3 dimensional orientation... cause then my brain's going to explodes