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Probability: Dice-rolling

  1. Feb 8, 2009 #1
    1. The problem statement, all variables and given/known data
    You roll two dice at the same time. Each time you get a 6 on a die you should throw it away and roll the other one. Otherwise, you keep rolling both of them. The game is over when you throw away both dice. What is the expected number of times you roll?


    2. Relevant equations

    Not sure.

    3. The attempt at a solution

    I tried defining a random variable called Y that has the form

    [tex]
    Y = \mathbf{T} \cdot \mathbf{X}
    [/tex]

    This is the dot product between random vectors X and T,
    where X = (X1 X2 X3) and T = (T1 T2 T3). Here T1 has value 1 if there's no 6 and zero otherwise. T2 has value 1 if there's one 6 and zero otherwise. T3 has value 1 if there are two sixes and zero otherwise. I'm thinking the X_i should be Bernoulli random variables, but am not sure. A monte-carlo simulation gives me 8.7, and I think this is right, but I have to show it analytically.

    Thanks.
     
  2. jcsd
  3. Feb 8, 2009 #2
    The number of rolls it takes each die to get a 6 is http://en.wikipedia.org/wiki/Geometric_distribution" [Broken]. You just need to compute the expected value of the maximum of the two times, which is easy by conditioning. (It's actually easier than that.)
     
    Last edited by a moderator: May 4, 2017
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