Probability Generating Functions

AI Thread Summary
Probability Generating Functions (PGFs) are used to analyze random variables, with the example given being H(s) = (1/3)(1+s+s^2) for random variable X. The user seeks to find the PGF for Y, defined as Y = X + 1, and is unsure how to proceed with the calculation. A response clarifies that the original PGF indicates equal probabilities for values 0, 1, and 2. The discussion concludes with the user expressing gratitude for the helpful information, noting that further exercises have clarified their understanding. Understanding PGFs is essential for analyzing the distributions of random variables effectively.
EthanW
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Hello,

I am trying to get the hang of Probability Generating Functions, but I don't quite understand them fully.

For example, I've got the PGF of a random variable X, called H:
H(s) = \frac{1}{3}\cdot(1+s+s^2)

Now, then there is a random variable Y, with Y = X + 1, and I want to solve the PGF of Y I do:
G_Y(s) = G_{x+1}(s) = E[s^{x+1}] = E[s^x]\cdot E<s> = ? </s>

I don't know how to go further at this point, can someone point me in the right direction?

Thanks.
 
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EthanW said:
Hello,

I am trying to get the hang of Probability Generating Functions, but I don't quite understand them fully.

For example, I've got the PGF of a random variable X, called H:
H(s) = \frac{1}{3}\cdot(1+s+s^2)

Now, then there is a random variable Y, with Y = X + 1, and I want to solve the PGF of Y I do:
G_Y(s) = G_{x+1}(s) = E[s^{x+1}] = E[s^x]\cdot E<s> = ? </s>

I don't know how to go further at this point, can someone point me in the right direction?

Thanks.


Your original PGF simply means that P(0) = P(1) = P(2) = 1/3.

If you want P(1) = P(2) = P(3) = 1/3, the generating function is

\frac{1}{3} (s + s^2 + s^3)
 
Thanks, very useful information. I made some other exercises and they've become more clear now. :)
 
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