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You have the expression for Q(r,t). We want the peak value as t varies. At the peak, consecutive terms will be about equal (same principle as finding maxima with calculus). So you write Q(r,t) = Q(r,t+1). Because of all the factorials involved (see the formula I posted for nCr), there will be a lot of cancellation of terms. When the smoke clears, you should have a relatively simple polynomial for t. This won't give a whole number, so try the whole numbers either side of what it does give. One of these two will be the peak term in the sequence.