Probability of numbers between 0 and 1

AI Thread Summary
To determine the probability that at least 5 out of the first 10 decimal places of a number between 0 and 1 are less than 5, one must first establish the probability of any given digit being less than 5, which is 0.5. This scenario can be modeled as a binomial probability problem, where the number of trials is 10 and the probability of success is 0.5. The calculation involves finding the cumulative probability of getting at least 5 successes (digits less than 5) in 10 trials. The discussion emphasizes the need to clarify whether the focus is on exactly five or at least five digits being less than 5, confirming that the interest lies in the latter. Understanding binomial distributions is crucial for solving this probability problem effectively.
deah
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anybody could help me how to solve this..
between nos. 0 and 1, what is the probability that 5 of its first 10 decimal places is less than 5?
 
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How would you first approach this problem yourself?
 
A.What is the probability that any given digit is less than 5?

B.What is the probability of 5 out of 10 digits being less than 5, using the probability in A?
 
In other words, it is a binomial probability problem!
 
Exactly five or at least five?
 
sorry..

it's at least five..
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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