Probability of selecting letters in alphabetic order

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To find the probability of selecting five letters in alphabetic order from a set of 26 tiles, one must first determine the total number of combinations of five letters, which is calculated as 26 choose 5. For any selected combination of five letters, there is only one arrangement that is in alphabetic order. Therefore, the probability of drawing five letters in alphabetic order is 1 divided by the number of arrangements of those letters, which is 5! or 120. This leads to a final probability of 1/120, illustrating that the total number of tiles does not affect the probability, only the number of letters drawn. Understanding this concept helps clarify the relationship between combinations and arrangements in probability.
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Homework Statement



There are 26 tiles in a bag, each with a different letter on it. You draw 5, without replacement. What is the probability that you pick the five letters in alphabetic order (e.g. C-H-R-T-W)

The Attempt at a Solution



The only way I could think of to do this was to find the total number of possible 5 letter sequences and the number of those sequences that are in alphabetic order, and then divide the two. There are 26P5=7893600 different sequences of letters. But I have not been able to think of a good way to calculate the number of those that are in alphabetic order. Any suggestions would be appreciated. Thank you!
 
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First try it with only 5 letters in the bag, then 6 letters. Try to see a pattern you can extend to 26 letters.
 
For every set of five letters, there is only one way to arrange it in alphabetic order. So the number of ways to choose five letters in alphabetic order is the same as the number of ways to choose five letters from 26.
 
Ah, that makes sense. So for each possible combination of 5 letters there are 5!=120 possible arrangements and only 1 that is in alphabetic order, so the probability is 1/120. It's interesting that it doesn't even matter how many tiles are in the bag, only how many you are picking at a time. Thanks, Dick.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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