- #1

GreenPrint

- 1,196

- 0

**Probability Question -- colored balls in 2 bowls -- Baye's formula?**

Bowl #1 contains 2 red balls and 2 white balls

Bowl #2 contains 3 red balls and 2 white ball

one bowl is chosen at random (each is equally likely)

(A) What is the probability of choosing a red ball?

Let R stand for choosing a red ball

[itex]B_{#}[/itex] = Bowel #

[itex]P(R) = P(B_{1})P(R|B_{1})+P(B_{2})P(R|B_{2})[/itex]

[itex]P(R) = \frac{1}{2} \frac{1}{2} + \frac{1}{2} + \frac{3}{4} = .625[/itex]

(B)

[itex]P(B_{1}) = P(R)P(B_{1}|R)[/itex]

I don't know how to calculate [itex]P(B_{1}|R)[/itex]. Do I need to use Baye's formula?

Thanks for any help! Hopefully I'm not making this to complicated again lol.

Last edited by a moderator: