Problem on Operational Amplifier

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Discussion Overview

The discussion revolves around the application of operational amplifiers (op-amps), specifically addressing a problem involving internal resistance and supply voltage in a non-ideal scenario. Participants explore concepts related to voltage comparators and the implications of non-ideal characteristics on output voltage.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether internal resistance and supply voltage should be considered when calculating output voltage (V_0) in their assignment.
  • Another suggests sketching an equivalent circuit to include non-ideal characteristics, implying this may affect the outcome.
  • A participant notes that the amplifier is in an open-loop configuration, prompting a discussion about the implications of this setup.
  • It is acknowledged that in an open-loop configuration, current flows into the op-amp, and the voltages at the inputs (V+ and V-) are not equal.
  • Participants discuss the behavior of the comparator, stating that if V+ > V-, the output voltage will be +Vs, and if V- > V+, it will be -Vs.
  • One participant asserts that since V- > V+, the output voltage will be -10V, while another agrees but notes the assumption of positive input voltage (Vi) is necessary.
  • There is a caution about ensuring that non-ideal characteristics do not leave the output in the active region instead of being saturated, with some participants indicating that the gain and input resistance are sufficiently high to avoid this issue.
  • Another participant introduces a new topic, requesting a circuit design that adds an AC signal to a variable DC signal, suggesting a potential shift in focus within the thread.

Areas of Agreement / Disagreement

Participants exhibit some agreement on the behavior of the comparator and the implications of the open-loop configuration. However, there remains uncertainty regarding the impact of non-ideal characteristics on the output voltage, and the discussion includes multiple viewpoints without a clear consensus.

Contextual Notes

Some assumptions about the ideal behavior of op-amps are challenged, particularly regarding internal resistance and supply voltage. The discussion also touches on the need for clarity on the input voltage's sign and the conditions under which the output may be affected by non-ideal characteristics.

Who May Find This Useful

Students and practitioners interested in operational amplifier applications, particularly in non-ideal scenarios, as well as those seeking clarification on voltage comparators and circuit design involving AC and DC signals.

lowqiumei
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Hi,

Just I really short question. I have attached my assignment as a picture file. Don't worry I am not asking you to give me a solution.

I just want to know, in the question it tells us that there is a internal resistance of 1MΩ, and a supply voltage of 10V. I am really confuse, as all the questions i have did so far I have assume as ideal and has never taken consideration of internal resistance and supply voltage.

So my question here is, to find V_0, do I have to consider the internal resistance and supply voltage in my working?
 

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lowqiumei said:
Hi,

Just I really short question. I have attached my assignment as a picture file. Don't worry I am not asking you to give me a solution.

I just want to know, in the question it tells us that there is a internal resistance of 1MΩ, and a supply voltage of 10V. I am really confuse, as all the questions i have did so far I have assume as ideal and has never taken consideration of internal resistance and supply voltage.

So my question here is, to find V_0, do I have to consider the internal resistance and supply voltage in my working?

You should be able to sketch an equivalent circuit where the non-ideal characteristics are included, and then conclude whether or not they will affect the outcome.
 
the amplifier in your diagram has no negative (or positive) feedback, it is 'open loop'. Do you realize what that means.
 
Yes, So means I can no longer assume that there is no current flowing into operational amplifier and V+ is not equal to V-. And I also know that this is a voltage comparator.
 
Since it is a comparator, Am i right to say that when:
V+ > V- the output voltage will be +Vs
V- > V+ the output voltage will be -Vs

In this question since V- > V+, can i safely say that the output voltage will be -10v ?
 
Yes, that is correct (altho no sign is given for Vi I think you can assume that it is +)
 
lowqiumei said:
Since it is a comparator, Am i right to say that when:
V+ > V- the output voltage will be +Vs
V- > V+ the output voltage will be -Vs

In this question since V- > V+, can i safely say that the output voltage will be -10v ?

In practice you can 'safely' say it if you've determined that the non-ideal characteristics of the op-amp won't leave the output in the active region rather than saturated (pegged to either supply rail). In this case the gain and input resistance happen to be sufficiently high so that this is not an issue.
 
Operational Amplifier

I need a circuit that adds an AC signal with magnitude of 25mV and a variable DC signal between 0 to 5V, and applies it to a diode.
 


yasef said:
I need a circuit that adds an AC signal with magnitude of 25mV and a variable DC signal between 0 to 5V, and applies it to a diode.

You might want to ask the question in the Electrical Engineering forum, or investigate "summing amplifier".
 

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