Problem with caclulatin forces in structure

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SUMMARY

The discussion revolves around calculating forces in a structural analysis problem involving two structures. The user attempts to apply static equilibrium principles by setting up six equations based on the forces of 450N and 300N, but finds that these equations reduce to only three unique equations. The user seeks clarification on additional conditions that must be satisfied for the forces to balance, emphasizing the need for all forces and moments to sum to zero.

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louike
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Hallo all, I have been working on a little problem.
I have to calculate the forces on a certain structure, but I can not seem to find the solution.

I have given a picture, drawing with my attempt and the drawing of how I try to solve it.

The first drawing is to find the first forces, those are easy.
Then I split the structure in 2 structures to find the other forces, however when I do this I get 2 structures with 3 equations, in total 6 equations. But when you try to work those 6 calculaitions, you will see they are the same (meaning those 6 equations are only 3 equations).

Any one who can help me out here?

The forces 450N and 300N are given.

http://img375.imageshack.us/my.php?image=teck0.jpg
http://img375.imageshack.us/my.php?image=teck0.jpg
The distances are in metres (drawing is not really accurate in scale:smile:)

As you can so I start of with calculating the force on A , then I find the forces in C.

But then I get stuck.
 
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You're obviously aware that all the forces must balance each other, i.e. they sum to zero.

What else should sum to zero here?p.s. Welcome to PF!
 
Redbelly98 said:
You're obviously aware that all the forces must balance each other, i.e. they sum to zero.

What else should sum to zero here?


p.s. Welcome to PF!

I do not know.

I just wrote down 3 equations for each drawing (1+2) meaning 6 in total, but they are the same.

1.

X forces: 450N + Dx + Bx = 0
Y: By - Ay - Dy = 0
M around B makes: +Ay. 0,15 -450. 0,25 - Dy.0,45 + Dx.0,1


for 2 its the same: they are the same then for 1.


so what can I do then?
 

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