Adel Makram said:
I have found a semi solution to the Doppler paradox. Regarding the interference pattern part, the light from both ends A` and B` has to reach a middle point in the embankment FOR (M) so as to enter into a slit and then double slit before projecting into screen. Now, The train observer sees the external observer moving from B` to A` direction with a velocity = -v. and when the 2 ends at the embankment received the light from A` and B`, he see that the light fro B` which happens first has to travel a longer distance than from A` to reach the middle of the embankment point. And also the accumulated phase change from B` and A` should be compensated when they reach M. SO the net effect on the screen will be black and bright strips which is the same result as the external observer
Part of the problem is you're trying to turn a thought experiment into a laboratory experiment. Not that that is a terrible thing to do, but in this case, we don't have the laboratory equipment necessary to set it up.
The thought experiment asks the question "How is it possible for the external observers to observe the same events as the internal observers, when both see an equal speed of light?" For some time, this question seeme more than a question, but a paradox; an enigma; the sort of question that couldn't possibly have a reasonable answer.
However, as so often happens, once the question is understood, the solution is forthcoming. The solution is to say that those events which appear simultaneous for the internal abservers, happen consecutively, back to front, for the external observers.
That answer is complete, and need not be embellished with further complication.
If you want to add into that set-up bunch of diffraction grating equipment and some fluorescent lights, so that the observers can test for red-shift and blue-shifting of the light, you're free to do so in your thought experiment, but I would agree with Doc Al, that it's irrelevant to the question of simultaneity.