Problem with use of 'velocity' of charged particle in lorentz force eq

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SUMMARY

The discussion centers on the application of the Lorentz force equation to a charged particle moving in a uniform magnetic field. When observed from an inertial frame, the particle experiences a force due to the magnetic field. However, when viewed from a moving reference frame, the particle's velocity changes to V - V', resulting in a different force calculation. The introduction of an electric field due to the Lorentz transformation of the magnetic field is crucial for resolving discrepancies between the two frames.

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  • Understanding of Lorentz force equation
  • Familiarity with magnetic and electric fields
  • Knowledge of reference frames in physics
  • Basic principles of Lorentz transformations
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  • Study the implications of Lorentz transformations on electromagnetic fields
  • Explore the derivation of the Lorentz force equation in different reference frames
  • Investigate the relationship between magnetic fields and induced electric fields
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Physicists, students of electromagnetism, and anyone studying the dynamics of charged particles in magnetic fields will benefit from this discussion.

pratikaman
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if we assume a charge particle enters in a uniform magnetic field with velocity V w.r.t inertial frame as shown fig. then according to the situation shown there will be force acting on particle due to magnetic field (neglecting B field induced due to charged particle itself). But now if we observe this situation from a frame of reference which is moving with velocity V' in direction of particle's velocity with respect to inertial frame then velocity of particle observed in that frame will be V-V'. then force on particle due to magnetic field will be less (As calculated by lorentz force equation) than as calculated in inetial frame.

what will be the right solution for this case?
 

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Are you implying/specifying/assuming that the magnetic field is fixed in relation to both reference frames?
 
There will now be an E field, becuse a Lorentz transformation of B produces an E field.
 

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