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Product States

  1. Mar 5, 2012 #1
    How do we know when we can write a product state for two systems, and situations when you need to use a sum of product states?

    If you have a product state for two systems, does it evolve into a sum?
     
  2. jcsd
  3. Mar 5, 2012 #2
    In general, the quantum state of the whole system is a sum of product states for the two (disjoint) subsystems, but often this quantum state can be factorized into a product of states for the two subsystems. And yes, depending on the Hamiltonian it is in principle possible for a product of quantum states to evolve in time into an entangled state, but usually the Hamiltonian is nicer than that.
     
  4. Mar 5, 2012 #3
    Okay so if we have two pairs of entangled photons:
    We'd write the whole state of both pairs as the sum of the product state (which would be two photons TENSOR two photons)?

    I dont even know if tensor is the right word (circle with x in it?)?
     
  5. Mar 5, 2012 #4
    Yes, exactly. And that symbol is a tensor product.

    If you want to see this all done in detail, you can read Sakurai, the standard graduate text on QM. Or at an undergraduate level Townsend does a good job of covering this ground, and it's relatively short.
     
  6. Mar 5, 2012 #5
    And when we write a sum of product states, they're entangled?
     
  7. Mar 5, 2012 #6
    If we write a quantum state as a sum of products of arbitrary states (they could be linearly dependent, for instance), then we may still be able to factor this state as a product of states, so there's not entanglement. If, however, it cannot be factored into a single product, then it's entangled.
     
  8. Mar 5, 2012 #7
    Now I'm confused, because Erich Joos is saying "When you have to use a sum of product terms, you have an entangled state"
     
  9. Mar 6, 2012 #8
    That's the point, when you have to use a sum, then it's entanglement. But if it's merely possible to write it using a sum, that need not be entanglement.
     
  10. Mar 6, 2012 #9
    Ah yes. That makes more sense. Thanks for pointing that out!
     
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