Products of Ethylene + Fluorine Reaction

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When ethylene (C2H4) reacts with fluorine gas (F2), two potential products can form based on the balancing of chemical equations. The first possibility yields two hydrogen fluoride (HF) molecules and two carbon tetrafluoride (CF4) molecules. The second possibility results in one carbon atom, two HF molecules, and one CF4 molecule. Both reactions are balanced, leading to uncertainty about which reaction pathway is more likely. The discussion suggests considering the reaction in terms of dissociation followed by a reaction with fluorine, prompting a question about the probability of each reaction occurring. The focus is on determining which of the two balanced reactions is more favorable in the presence of fluorine.
tandoorichicken
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just a basic rookie question. What are the products when ethylene reacts with fluorine gas (i.e., burned in presence of fluorine)?

I was given the following data:
H_2 + F_2 \rightarrow 2HF \Delta H^{o} = -537 kJ
C + 2F_2 \rightarrow CF_4 \Delta H^{o} = -680 kJ
2C + 2H_2 \rightarrow C_2 H_4 \Delta H^{o} = +52.3 kJ

I used the starting formula C_2 H_4 + 4F_2

I balanced out equations and got two possibilities, and I'm not sure which one to go with. In one, it forms 2 hydrogen molecules and 2 carbon tetrafluoride, and in the other it forms 1 C, 2 HF and 1 carbon tetrafluoride. BOTH of these balance out and I don't know which one to go with.
 
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Think of the reaction in terms of a dissociation (eqn #3 backwards) followed by a reaction with fluorine. Which of the two reactions with fluorine has a higher probability ?
 

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