Projectile Motion - baseball popup

AI Thread Summary
The discussion focuses on calculating the launch angle of a baseball that remains airborne for 6.3 seconds and lands 83 meters away. The equations for horizontal and vertical velocity components, Vx and Vy, are utilized in the analysis. The vertical velocity is determined to be 30.87 m/s, while the horizontal velocity is calculated as 13.17 m/s. The tangent of the launch angle is derived from the ratio of Vy to Vx, resulting in an angle of approximately 66 degrees. The calculations highlight the relationship between time of flight, horizontal distance, and launch angle in projectile motion.
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Projectile Motion -- baseball popup

Homework Statement


A baseball is popped up, remaining aloft for 6.3 s before being caught at a horizontal distance of 83 m from the starting point. What was the launch angle?


Homework Equations


vx = vcostheta
vy = vcostheta

The Attempt at a Solution


I tried solving for vx and vy then take those and find the arctan but then there was an erroron my caclculator. Besides, I think I'm doing something wrong.
 
Physics news on Phys.org


Vx= V*CosQ
Vy=V*SinQ
t= 2*Vy/g=6.3 =>Vy=30.87 m/s
Range= Vx*t=83m => Vx=13.17 m/s
Vy/Vx=TanQ=66 Degrees
 

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