Projectile motion but with resistive force

AI Thread Summary
To solve the projectile motion problem with resistive force, start by establishing the differential equation for the horizontal component of velocity, where the resistive force is R_x = -b v_x. Given the mass of the projectile is 10 kg and the resistive coefficient b is 10 kg/s, the equation can be expressed as m \dot{v_x} = -b v_x. This leads to a first-order linear differential equation that can be solved using standard techniques. The solution will yield the horizontal and vertical coordinates as functions of time, incorporating the effects of the resistive force. Understanding the relationship between the forces and acceleration is crucial for deriving the complete solution.
tubworld
Messages
38
Reaction score
0
I have this question:

A 10kg projectile is launched with an initial speed of 100m/s at an elevation of 35 degrees. The resistive force is R = -bv , where b =10kg/s.

Determine the horizontal and vertical component coordinates of the projectile as functions of time.

How do I do this?? I urgently need the complete solution to this! Thanx!
 
Physics news on Phys.org
Basically you're looking for a differential equation for the x-component of the velocity. This is not difficult to find because you can work with this component without thinking about the y-component. You know that \vec{R}=-b\vec{v}, so then R_x=-bv_x. You also know that \vec{F}=\vec{R}=m\vec{a}=m\vec{\dot{v}}, so R_x=m\dot{v_x}. Substitute for R. Do you recognize the solution of the differential equation you get?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top