Projectile Motion: Find Initial Velocity of Diver Springing From 3m Board

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AI Thread Summary
A diver springs from a 3-meter board and hits the water at a speed of 9.10 m/s at a 75.0° angle. The initial velocity was calculated to be 4.9 m/s, but the user struggled with determining the direction. Using kinematic equations, they found the horizontal component of velocity (vx) to be 3.85 m/s and the vertical component (vy) to be 8.79 m/s. The discussion highlights the importance of understanding velocity components in projectile motion. Ultimately, the user successfully arrived at the answer with assistance from others.
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Homework Statement



A diver springs upward from a board that is three meters above the water. At the instant she contacts the water her speed is 9.10 m/s and her body makes an angle of 75.0° with respect to the horizontal surface of the water. Determine her initial velocity, both magnitude and direction.

Homework Equations



Kinematics equations :)

The Attempt at a Solution



I already got 4.9 m/s as the magnitude of the vector, but can't seem to get the direction in degrees!
 
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What's the horizontal component of her velocity?
 
i just used the (9.1)squared=v initial squared +2(-9.8)(-3) and got the v initial magnitude...i don't know how to get the components is why I'm confused actually
 
Hint: You have her final speed and angle. Use it!
 
ok, so i got 3.85 as vx and for vy =8.79 but how does that help me?
 
ladolce said:
ok, so i got 3.85 as vx
Show how you got that value.

but how does that help me?
Does the horizontal component of velocity change as the diver falls?
 
Haha I got the answer...thanks for your help =)
 
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