Projectile motion in a spring loaded gun

In summary, the conversation discusses a Turbo Booster toy that launches a 60-gram "insect" glider using a helical spring. The launcher is made of carbon steel wire with specific dimensions. The task is to calculate the number of turns in the spring to provide the necessary energy for the glider to travel approximately 8 meters. This involves using conservation of energy and the equation for the spring constant of a helical spring.
  • #1
Darknes51986
10
0

Homework Statement


1. A Turbo Booster toy that launches a 60-gram “insect” glider projectile by compressing a helical spring and then releasing the spring when the trigger is pulled. When pointed upward the glider should ascend approximately 8 m before falling. The launcher is made with carbon steel wire, with a diameter of d=1.1 mm. The coil diameter is D=10 mm. Calculate the number of turns N in the spring such that it would provide the necessary energy to the glider. The total working deflection is x=150 mm with a clash allowance of 10%.

Homework Equations


I need to used conservation of energy to find initial velocity and spring constant I believe. Final velocity is 0. Not sure how to find the number of turns in the spring though.

KE=1/2*m*V^2
PE=m*g*h

The Attempt at a Solution



g=9.81 m/s^2 gravity
d=1.1 mm wire diameter
D=10 mm col diameter
m=60 gm mass of toy
x=150 mm working deflection
dist= 8 m distance traveled

C=D/d=10/1.1= 9.091 spring index
G=11.2*10^6 psi (for carbon steel)
k=?
V=?

somehow need number of turns
 
Last edited:
Physics news on Phys.org
  • #2
trying to bump this up
 
  • #3
This looks like it's outside the scope of a standard introductory physics class, which normally does not discuss how the number of turns and wire diameter related to the spring constant.

I am wondering if your professor has given you additional material on this?

At any rate, it is possible to find the spring constant k using conservation of energy methods.
 
  • #4
This is definitely a combination of physics and mechanical design. You have the correct approach. Conservation of energy will allow you to calculate the spring constant needed to impart the correct amount of energy needed to reach 8 m. From here, you can use the equation for the spring constant of a helical spring (as obtained from Shigley's Chapter 10-3)
[tex] k = \frac{d^4 G}{8D^3 N}[/tex]
Where d is the wire diameter, D is the mean spring diameter, G is the shear modulus of the material, and N is the...tada, number of turns in the spring.

Good luck,

p.s. tex is still down, so try to read this for the spring constant
k = (d^4 * G) / (8D^3 N)
 

1. How does a spring loaded gun work?

A spring loaded gun uses the potential energy stored in a compressed spring to propel a projectile forward. When the trigger is pulled, the spring is released and rapidly expands, pushing the projectile out of the gun.

2. What factors affect the range of a projectile in a spring loaded gun?

The range of a projectile in a spring loaded gun is affected by the initial velocity of the projectile, the angle at which it is launched, and the force of gravity. Other factors such as air resistance and the weight of the projectile can also play a role.

3. How do you calculate the maximum height of a projectile launched from a spring loaded gun?

The maximum height of a projectile launched from a spring loaded gun can be calculated using the equation h = (v2sin2θ)/2g, where h is the maximum height, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

4. How does the force of the spring affect the velocity of the projectile?

The force of the spring directly affects the velocity of the projectile. The greater the force of the spring, the greater the initial velocity of the projectile will be. This results in a longer range and higher maximum height for the projectile.

5. Can the range of a projectile in a spring loaded gun be increased by changing the spring?

Yes, the range of a projectile can be increased by changing the spring in a spring loaded gun. A stronger or more compressed spring will result in a greater initial velocity and therefore a longer range for the projectile.

Similar threads

  • Introductory Physics Homework Help
Replies
15
Views
327
  • Introductory Physics Homework Help
Replies
22
Views
4K
  • Introductory Physics Homework Help
Replies
2
Views
739
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
8K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
26
Views
4K
Back
Top