Projectile Motion Problems: Solving for Time with Given Initial Speed and Height

  • Thread starter Thread starter Sophialiu609
  • Start date Start date
AI Thread Summary
To solve projectile motion problems involving time, the key equation used is h = rt - 4.9t², where h is height, r is initial speed, and t is time. For the first problem, a projectile fired upward with an initial speed of 2940 m/s returns to the ground after 10 minutes, calculated by setting displacement to zero. The second problem involves a ball thrown from a 98m tower with an initial speed of 39.2 m/s, leading to a solution that requires solving a quadratic equation. It's important to ensure that time is converted to the correct units, and the initial setup of the equations must be clear before plugging in values. The discussion emphasizes the importance of understanding the equations and the physical meaning of the variables involved.
Sophialiu609
Messages
10
Reaction score
0
t=number of seconds
h=height
r=initial speed
How do you solve these two problems?
1. A projectile is fired upward with an initial speed of 2940 m/s. After how many minutes does it hit the ground?
2. A ball is thrown upward from the top of a 98m tower with an initial speed of 39.2 m/s. When does it hit the ground?
I don't understand how you can find the answers to these types of problems
 
Physics news on Phys.org
Help PLEASE!
I got this far on the second one...
h=rt- 4.9t²
-98=39.2t-4.9t²
-20=8t-t²
0=-(t²-8t -20)
0=-(t-10)(t+2)
(t-10)=0 (t+2)=0
t=10 t=-2
 
Last edited:
For the first:
If you don't need the height then why are you calculating it ?
Try Vf = Vi + at
Where t would be time of flight & Vf,Vi final and initial velocity respectively
 
Last edited:
Well, I'm supposed to put the problem into that formula, that's what I'm confused about.
 
Don't forget to convert time to minutes b/c the answer you will get is in seconds.
 
For the first, if it's fired from the ground and lands on the ground, what is h (often times, more appropriately written as \Deltah)?
 
Sophialiu609 said:
Well, I'm supposed to put the problem into that formula, that's what I'm confused about.

For the first question: you can use the same equation as you did for problem #2. If the projectile returns to the ground, what is its displacement? What does that make h in your equation?
 
Ok, so what I have so far is
0=2940t/60 -4.9t^2/60
0=-4.9t(t/60 -1)
0=-4.9t(t-1/60)
0=-4.9t(t-1)
t={0,1}
Is that right?
 
0=2940t-4.9t²
60 60
0=2940t-4.9t²
0=600t-t²
0=-t(t-600)
-t=0 (t-600)=0
t=0 t=600

or is this right?
 
  • #10
Just a little tip, you might want to work through things in algebra before you number plug :)
 
  • #11
Would time 0 make sense as an answer?

And what units are your answers in?
 
  • #12
0 wouldn't make sense as an answer, my answer is in minutes~I think... but now I'm more confused...
 
  • #13
Is it 10 minutes...?
 
  • #14
Sophialiu609 said:
Is it 10 minutes...?
Stop guessing. What equation are you using?

And before plugging values into your equation, let's SOLVE for the variable we want.
 
  • #15
The one I posted as the title!
h=rt-4.9t^2
 
  • #16
Sophialiu609 said:
The one I posted as the title!
h=rt-4.9t^2
Well looks right to me. You have it in terms of minutes, so there you go.
 
  • #17
So was my answer correct? 10 minutes? Because 600/60=10
 
  • #18
oh ohkay, thank you i didn't see the second page
 
Back
Top