Projectile motion without time or initial velocity

AI Thread Summary
To determine the velocity required to throw a snowball from a height of 11m at a 25-degree angle to hit a target 1.5m high and 37m away, two key equations are utilized: horizontal and vertical motion equations. The horizontal component of velocity (Vx) is calculated as v Cos(25), while the vertical component (Vy) is v Sin(25). The challenge lies in solving for the initial velocity without time or initial velocity provided. The snowball must cover both the horizontal distance and vertical drop simultaneously, leading to a system of equations that must be solved together. Understanding the relationship between these components is crucial for finding the required throw velocity.
entwistle 89
Messages
1
Reaction score
0

Homework Statement


You throw a snowball from a height of 11m at an angle of 25 degrees to the horizontal to hit your teacher in the chest (1.5m from the ground) who is on the sidewalk 37m from you horizontally, at what velocity must you throw the snowball to hit your teacher


Homework Equations


d= v(t) + 1/2 a (t)^2


The Attempt at a Solution



Vx= v Cos(25)
Vy= v Sin(25)

I have no clue where to go from here to be completely honest
 
Physics news on Phys.org
hint: you have 2 equations in two variables
the snowball should travel the given horizontal distance and also the given vertical distance in the same time
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top