A rocket-powered hockey puck has a thrust of 1.20N and a total mass of 1.50kg. It is released from rest on a frictionless table, 3.20m from the edge of a 3.60m p. The front of the rocket is pointed directly toward the edge. I have found that the acceleration of the hockey puck in the x-direction is 0.8m/s/s because of the F_thrust/m_puck = a_x thing that was found in Newton's Second Law representation of the forces in the x-direction. I also found that the time between the moment when the puck falls off of the table to when it hits the ground, by virtue of the fact that the puck falls under the influence of gravity only, is 0.857s. [tex]\Sigma[/tex](F_x) = F_thrust = m_puck * a_x [tex]\Sigma[/tex](F_y) = n - w = m_puck * a_y Now, with the picture and these things here, I have a little bit of trouble find the correct kinematics equations to put these pieces of information into a solution.