Calculating Distance for Horizontal and Vertical Movements

[Mathysics]

ummm i don't know how to calculate the distance if:

horizontal- v=2, u=2,a=0, s=?
Vertical- v=?, u=0, a=9.8 s=1

 

[LowlyPion]

What equation relates v,u,a, and s?

v² = u² + 2*a*s

Is that what you are talking about?

 

[nlightner]

To calculate distance for horizontal and vertical movements, we can use the formula d = ut + 1/2at^2, where d is the distance, u is the initial velocity, a is the acceleration, and t is the time.

For the given values, in the horizontal movement, the acceleration (a) is 0, which means that the object is moving at a constant velocity. Therefore, the distance (s) can be calculated by simply multiplying the initial velocity (u) by the time (t), which in this case is 2 seconds. So, s = 2 x 2 = 4 meters.

In the vertical movement, the initial velocity (u) is 0, which means that the object starts from rest. The acceleration (a) is 9.8 m/s^2, which is the acceleration due to gravity. The time (t) is given as 1 second. Using the formula, s = 0 x 1 + 1/2 x 9.8 x (1)^2 = 4.9 meters.

Therefore, the distance for horizontal movement is 4 meters and for vertical movement is 4.9 meters. It is important to note that this calculation assumes that the object is moving in a vacuum and there is no air resistance. In real-life scenarios, the distance may vary due to external factors such as air resistance and friction.