- #1
Jon.G
- 45
- 0
Homework Statement
A projectile is fired in such a way that its maximum height is a factor of 4 times its
horizontal range. Find the launch angle in degrees
Homework Equations
[itex]h_{max}=\frac{V^{2}_{0}sin^{2}\theta}{2g}
Range=\frac{V^{2}_{0}sin2\theta}{g}[/itex]
The Attempt at a Solution
I set h=4R giving
[itex]sin^{2}(\theta)=8sin(2\theta); [/itex]
[itex]sin^{2}(\theta)=16sin(\theta)cos(\theta); [/itex]
[itex]sin(\theta)=16cos(\theta); [/itex]
[itex]tan(\theta)=16 [/itex]
[itex]\theta=86^{o} [/itex]
but the answer is apparently 38.66 degrees.
So I assumed that I had misinterpreted the question, and in fact R=4h, however doing this I got an angle of 45 degrees.
I'm not sure where I've gone wrong