Projectile with Air Resistance

AI Thread Summary
The discussion explores the effects of air resistance on projectile motion, particularly focusing on how mass influences distance traveled. It is established that a more massive object experiences less acceleration due to air resistance, suggesting it should travel further than a lighter object under equal conditions. However, experimental results indicated that the heavier object traveled less distance, attributed to the limitations of the projectile launcher's energy output. The conversation highlights the importance of considering launch conditions, such as height differences and optimal angles, which deviate from the traditional 45 degrees in the presence of air resistance. Ultimately, the participants agree that under ideal conditions, the heavier object would outperform the lighter one in terms of range.
glenn101
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Hey all, I'm new to this forums.
My question is this, I've been learning about projectiles and I came across a thought regarding air resistance. For example if you have a more massive object (more kg) does it fall less distance(range) because of the addition of vectors of mg(weight force which would be bigger due to bigger m) and the air resistance force which will give a bigger net force? maybe I'm just confused.
Any help would be great:smile:
 
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Hi, glen101!

Let us assume that two projectiles, A and B are equal in shape, so that BOTH experience an air resistance force of type, say, -k\vec{v}, i.e, the constant k-value is equal for both projectiles.

Now, let us say that the mass of A is bigger than that of B.

Thus, Newton's 2.law for both objects can be written as:
\vec{g}-\frac{k}{m_{A}}\vec{v}=\vec{a}_{A}
\vec{g}-\frac{k}{m_{B}}\vec{v}=\vec{a}_{B}
\vec{g} being the acceleration due to gravity.
Now, if A and B at some instant (say, initially), have the SAME velocity, it follows that the acceleration term induced by the air resistance is LESS on the more massive object A, because \frac{k}{m_{A}} is less than \frac{k}{m_{B}}.

Thus, the heavier object should travel the furthest distance when beginning from equal conditions.
 
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thanks for the reply arildno!:smile:
I am intrigued that by what you are saying suggests that the more massive object should travel the furtherest distance as I have conducted an experiment launching a mass with a projectile launcher, and by my results it has shown that the more massive object travels less distance? would this be because the projectile launchers spring can only produce a certain amount of elastic potential energy to the mass thus the bigger mass consumes more energy during its flight making it move a shorter distance? oh and with the experiment I think the launch height and landing height are a bit different, not sure of that makes much of a difference however.
 
Putting it a bit whimsically, it's harder for air resistance to slow down the more massive object, because it has more momentum. (Assuming equal initial speeds)

Of course, it would take more energy to get the more massive object accelerated up to the same speed as the lighter one. It's interesting to muse about how air resistance will affect the range of the projectile if they are given identical initial energies instead of velocities.
 
glenn101 said:
more massive object ... projectile launchers spring
It's not a fair comparason, the spring won't launch the more massive object with the same speed as it would the less massive object.
 
Thank you all for the replies.
And you are very right Jeff Ried, I see the flaw in the experiment. And so if I had perfect conditions I would see that the more massive objects travels further distance due to the air resistance effect.
 
Also, you must be careful. When you are doing projectile motion with air resistance, the optimal angle is no longer 45 degrees w.r.t. the horizontal.
 
@ csprof2000
yes that is true, also having the difference of launch height and landing height alters 45 degrees as the optimum angle. I have stated that in a report I am writing.
 
Well, you should do more than state it... you should compare the two masses based on optimal trajectories, no? Each will have a different one.
 
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