Projectiles launched at an angle not sure if i posted this already?

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A diver pushes off horizontally from a 35 m cliff and must clear rocks extending 5 m from the base. The time in the air is calculated as approximately 2.67 seconds using the equation for vertical motion. The initial velocity required to clear the rocks is determined to be 1.85 m/s in the horizontal direction. The vertical component of the velocity is zero since the diver pushes off horizontally. The discussion clarifies the misunderstanding about the need for a vertical velocity component in this scenario.
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Homework Statement



A diver pushes off horizontally from a cliff 35 m above the water, and they must clear rocks that extend 5 m from the base of the cliff. (a)What minimum pushoff speed is necessary to clear the rocks? (b)How long are they in the air?

Homework Equations



for (b) t=square root of 35/4.9=2.67 s I understand how to derive the time equation.
for (b) y=v(y direction)t+1/2at^2 x=v(x direction)t

The Attempt at a Solution



I solved time already, and I got 1.85 m/s for the initial velocity in the x direction, but I can't get the correct initial velocity in the y direction. I am not even sure what I am doing wrong but its frustrating.
 
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thats actually not projectiles launched at an angle its horizontal projectile motion sorry-I was looking at an angled problem also, which I could use help with too.
 
aly1201 said:

Homework Statement



A diver pushes off horizontally from a cliff 35 m above the water, and they must clear rocks that extend 5 m from the base of the cliff. (a)What minimum pushoff speed is necessary to clear the rocks? (b)How long are they in the air?

Homework Equations



for (b) t=square root of 35/4.9=2.67 s I understand how to derive the time equation.
for (b) y=v(y direction)t+1/2at^2 x=v(x direction)t

The Attempt at a Solution



I solved time already, and I got 1.85 m/s for the initial velocity in the x direction, but I can't get the correct initial velocity in the y direction. I am not even sure what I am doing wrong but its frustrating.

The initial y velocity is "given" in the problem. It is zero, since he pushes off horizontally.
 
Oh ok, so I don't even have to solve for that. So the answer is really the initial velocity in the x direction? 1.85 m/s?
 
Yes.
 
Ok thanks!
 
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