Proof Complex Numbers: How to Prove |z1|^2/|z2|^2 = |z1/z2|^2

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SUMMARY

The proof of the equation |z1|^2/|z2|^2 = |z1/z2|^2 is established using the properties of complex numbers. By defining z1 as a + jb and z2 as l + jm, the left-hand side (LHS) is calculated by taking the modulus, resulting in a^2 + b^2. The right-hand side (RHS) is derived by rationalizing the numerator and denominator of z1/z2, leading to the conclusion that LHS equals RHS through separation of real and imaginary parts.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with modulus of complex numbers
  • Knowledge of polar representation of complex numbers
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of complex number division
  • Learn about polar representation of complex numbers
  • Explore proofs involving modulus and argument of complex numbers
  • Investigate applications of complex numbers in engineering and physics
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Students and educators in mathematics, particularly those focusing on complex analysis, as well as anyone interested in understanding the properties and proofs related to complex numbers.

Suni
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hello

could someone please help me out with proving the following:
|z1|^2/|z2|^2 = |z1/z2|^2

...with complex numbers

sorry I am not familiar with the coding here yet so i can't write that properly
 
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How is division defined on the complex numbers?
Use that to get the result, alternatively use polar representation of the numbers.
 
simply define z1 = a + jb and z2 = l + jm;
LHS - take modulus of each and keep it aside...i.e., a^2 + b^2 is modulus;
RHS - Rationalise the den. & num., i.e, z1/z2 = (a + jb)*(l - jm)/(l2 + m2);
separate out the real & imaginary parts...u'll find LHS = RHS...
 

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