Proof Complex Numbers: How to Prove |z1|^2/|z2|^2 = |z1/z2|^2

AI Thread Summary
To prove the equation |z1|^2/|z2|^2 = |z1/z2|^2 for complex numbers, one can start by defining z1 and z2 in their standard forms, z1 = a + jb and z2 = l + jm. The left-hand side (LHS) involves calculating the modulus of each complex number, resulting in a^2 + b^2 for |z1|^2 and l^2 + m^2 for |z2|^2. For the right-hand side (RHS), the division of complex numbers can be rationalized by multiplying by the conjugate, leading to the expression (a + jb)(l - jm)/(l^2 + m^2). By separating the real and imaginary parts, it can be shown that the LHS equals the RHS, thus proving the equation. This method effectively demonstrates the relationship between the moduli of complex numbers and their division.
Suni
Messages
13
Reaction score
0
hello

could someone please help me out with proving the following:
|z1|^2/|z2|^2 = |z1/z2|^2

...with complex numbers

sorry I am not familiar with the coding here yet so i can't write that properly
 
Mathematics news on Phys.org
How is division defined on the complex numbers?
Use that to get the result, alternatively use polar representation of the numbers.
 
simply define z1 = a + jb and z2 = l + jm;
LHS - take modulus of each and keep it aside...i.e., a^2 + b^2 is modulus;
RHS - Rationalise the den. & num., i.e, z1/z2 = (a + jb)*(l - jm)/(l2 + m2);
seperate out the real & imaginary parts...u'll find LHS = RHS...
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Back
Top