iamsmooth
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Homework Statement
Prove that:
2^n \geq n + 5 for all integer n > 5
Homework Equations
n/a
The Attempt at a Solution
This is what I did, just want to see if it's right.
Using mathematical induction:
Basis step:
When n = 3,
2^3 \geq 3 + 5
Since 8 = 8, base case is proven
Inductive step:
Assume 2^k \geq k + 5 for all integers k greater or equal to n.
We want to prove that 2^{k+1} \geq k + 1 + 5
Using our assumption, 2^k \geq k + 5, I know that:
2(2^k) \geq 2(k + 5)
=2^{k+1} \geq 2k + 10
From here, if I can prove 2k+10 is greater or equal to k+6, then it will prove
2^{k+1} \geq k + 6
So:
2k+10 \geq k + 6
2k \geq k - 4
k \geq -4
Thus is proven because k was said to be greater or equal to n which is at least 3. So the inequality is true.
Since inductive step is proven, 2^3 \geq 3 + 5 must be true.
QEDDoes this proof stand? I haven't had much practice with inequalities... so I'm very unsure about this proof.
Thanks.
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