Proof for a higher level math class

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Homework Statement



ac | bc if and only if a | b (Note that this is really two implications.)



2. The attempt at a solution

The only way I can see going about this proof is by using examples. I know that in ac | bc the c will cancel out in both, but I don't know how to properly word the proof. Any suggestions would be greatly helpful.
 
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aesailor said:

Homework Statement



ac | bc if and only if a | b (Note that this is really two implications.)



2. The attempt at a solution

The only way I can see going about this proof is by using examples. I know that in ac | bc the c will cancel out in both, but I don't know how to properly word the proof. Any suggestions would be greatly helpful.
You can use examples to disprove a statement (these are called counterexamples), but you can't use examples to prove a statement.

For the direction ac | bc ==> a | b, since ac divides bc, then bc must be some integer multiple of ac, so bc = k * ac, for some integer k. Can you show that this implies that b must be an integer multiple of a?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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