PROOF for: P(x) = anxn + an-1xn-1 + 90 HELP

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PROOF for: P(x) = anxn + an-1xn-1 + ... 90 HELP!

Homework Statement


P(x) = anxn + an-1xn-1 + ... +90

Homework Equations


1

The Attempt at a Solution


all day...nothing

I need some guidence with this Proof. Google isn't helping much. I have no idea how to do this.
 
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I have no idea what you are trying to prove. Can you state the original question?
 


I need a proof for

P(x) = anxn + an-1xn-1 + ... +90

related to the fundamental thorem of algebra

if someone could give me wth a proof for the FTA it would be appreciated just as much!
 


Proofs of FTA you can find on-line. That doesn't change the fact that P(x) = anxn + an-1xn-1 + ... +90 is not a statement you can prove. Is it supposed to be definition of P(x) or what? What are you supposed to prove?
 


I really don't know my proofessor just gave it to me to make up for a missed test what CAN you do with it?... cause i don't know where to start
 


I don't think anyone would know where to start. I really think you misunderstood the question. You might ask for clarification.
 


ohh well could some one help me prove that Z=a+bi exists?
 


We finally figured out that you meant
P(x)= a_nx^n+ a_{n-1}x^{n-1}+ \cdot\cdot\cdot+ 90
but that simply defines a polynomial. It doesn't say anything about the polynomial so there is nothing to be proved.
 


I think I finally understand what the OP is trying to say in this and the other thread he has started. Given the polynomial P(x) = anxn + an-1xn-1 + ... + 90, the FTA says that there exists at least one number z = a + bi such that P(z) = 0.

The OP is extremely vague on what he needs to do, but I think he wants to prove the FTA for this polynomial.
 
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'...90'?? As long as we are playing guessing games, I'm going to take a guess that the '90' is a distorted reading of 'a0'. There's nothing special about that polynomial. The OP must want a general proof of the FTA.
 
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