Proof for Problem 1.1.1 of Shankars Prin of QM

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The discussion centers around proving that |-V> = -|V> in quantum mechanics, specifically referencing Shankar's Principles of Quantum Mechanics. Participants express confusion over the proof's requirements, emphasizing the need for rigorous justification in mathematical reasoning. The proof begins with the equation |V> + (-|V>) = 0|V> = |0>, leading to the conclusion that |W> = |-V>. There is a mention of the axiom that states 1V = V, which is not explicitly stated in Shankar's text but is crucial for understanding linear spaces. The conversation highlights the importance of clarity and foundational principles in quantum mechanics proofs.
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I think I may be over-thinking this as I have had one formal course in QM and an independent study course in QM, but any help is MORE THAN GREATLY APPRECIATED!

Homework Statement



Prove that |-V> = -|V>


Homework Equations



He instructs us to begin with |V> + (-|V>) = 0|V> = |0>


The Attempt at a Solution



Let -|V> = |W>

Then

|V> + |W> = 0|V> = |0>

which implies that

|W> = |-V> ?

I'm really confused.
 
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Okay, first I think you mean problem 1.1.2, unless you have a different edition.
This is the kind of proof where you have to doubt everything. Act as if you are in a mathematical minefield. Only do the things you can completely justify.

I find myself wanting to say that 1V = V, but that actually isn't an axiom...

Assuming that for the moment,
V + (-1)V = 1V + (-1)V = (1 + -1)V = 0V = 0 (by part 1 of the same problem)
And thus (-1)V is the unique vector -V such that V + -V = 0

Looking up in other books, 1V = V is listed as an eighth axiom for linear spaces. Shankar described it by interpretation in a paragraph, but didn't actually state it overtly as an axiom.
 
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