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Proof, intersection and sum of vector spaces

  1. Jan 11, 2009 #1
    Hello,
    how to prove this:
    [tex]V^{\bot}\cap W^{\bot}=(V+W)^{\bot}[/tex]
    Thanks
     
  2. jcsd
  3. Jan 11, 2009 #2

    jambaugh

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    It is a "simple" matter of proving an element in the left-hand side is in the right-hand side and vis versa by parsing the definitions. But you'll learn little by seeing it done. You need to go through the steps of discovering the tricky details and resolving them so you appreciate the implications.
     
  4. Jan 11, 2009 #3
    Could you show me, how to do it?
     
  5. Jan 11, 2009 #4

    jambaugh

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    Yes but I'd rather you show me some start first. I take it this is an assignment in studying linear algebra. The point of an assignment if for you to puzzle through the problem and thereby learn.

    I'll start you by pointing out that if a vector [itex]v[/itex] is in the subspace [itex]U^\perp[/itex] then it must be perpendicular to all elements of the subspace [itex]U[/itex].
     
  6. Jan 12, 2009 #5
    I know this:
    [tex]\left(v\in V^{\bot}\wedge v\in W^{\bot}\right)\Rightarrow\left(v\in V^{\bot}\cap W^{\bot}\right)[/tex]
    [tex]\left(x\in V\wedge x\in W\right)\Rightarrow\left(x\in V\cap W\right)[/tex]
    I can also write that
    [tex]v^Tx=0\,;\; x\in V, v\in V^{\bot}[/tex]
    [tex]w^Ty=0\,;\; y\in W, w\in W^{\bot}[/tex]
     
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