Proof of convergent sequences

e179285
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How can we prove this statement?


It two subsequences (a2n) and (a2n-1) converge to the same value,then (an)) converges to that value also.
 
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hi e179285! :smile:

just write out the δ,ε definition twice, once for each series, then adapt it :wink:

(instead of δ, and x < δ, you use n, and n > N)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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