Proof of Polynomial Countability

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SUMMARY

The discussion centers on proving the countability of the set P(n), which consists of all polynomials of degree n with integer coefficients. The initial proof by induction starts with P(0) as countable, since it includes all constant polynomials. The transition from P(1) to P(n) is established by expressing P(n+1) in terms of P(n) and identifying additional countable terms. Ultimately, the conclusion is that the union of all countable sets of polynomials results in a countable set of all polynomials with integer coefficients.

PREREQUISITES
  • Understanding of mathematical induction
  • Familiarity with polynomial functions and their properties
  • Knowledge of countable versus uncountable sets
  • Basic concepts of set theory
NEXT STEPS
  • Study the principles of mathematical induction in depth
  • Explore the properties of polynomial functions, particularly in relation to their coefficients
  • Research countability in set theory, focusing on unions of countable sets
  • Examine examples of countable sets beyond polynomials, such as rational numbers
USEFUL FOR

Mathematics students, educators, and anyone interested in set theory and the properties of polynomials will benefit from this discussion.

Shaikhob
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Homework Statement


Let P(n) be the set of all polynomial of degree n with integer coefficients. Prove that P(n) is countable, then show that all polynomials with integer coefficients is a countable set.

2. The attempt at a solution
For this problem the book gives me a hint that using induction is one way to prove this. So by going off this I say that P(0) is countable since it is the set of all constants. After this I say that P(1) is countable since P(1) = ax + P(0) in which a ε A and A = {z: z ε Z, z ≠ 0}. Now my problem is that I do not know how to make the jump from P(1) to P(n) and then to P(n+1). For the second part of the question I know that all polynomials with integer coefficients are countable since if we were to take a union of all the sets they would be countable since the union of countable sets are countable.
 
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Hi, welcome to PF.

Looks like you already got all the components in place for a proof by induction.
Suppose that you have proven that P(n) is countable... can you write P(n + 1) in terms of P(n)?
 
hint: which terms are in P(n+1) that AREN'T in P(n)?

can you think of a way to write p(x) in P(n+1) as:

"something" + q(x), where q(x) is in P(n)?

maybe the "somethings" might be countable...
 

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