- #1
Faisal Moshiur
- 15
- 0
If we define Si=(1/2)× (reduced Planck's const)×sigma
Then what will be (sigma dot vect{A})multiplied by (Sigma dot vect{B})
Here (sigma)i is Pauli matrix.
Next one is, what will we get from simplifying
<Alpha|vect{S}|Alpha> where vect{S} is spin vector & |Apha>is equal to " exp[{i×(vect{S} dot (n_hat))× Theta/(reduced Planck's const)}]
Then what will be (sigma dot vect{A})multiplied by (Sigma dot vect{B})
Here (sigma)i is Pauli matrix.
Next one is, what will we get from simplifying
<Alpha|vect{S}|Alpha> where vect{S} is spin vector & |Apha>is equal to " exp[{i×(vect{S} dot (n_hat))× Theta/(reduced Planck's const)}]