- #1
stanley.st
- 31
- 0
Hello,
can you help me with the proof? If A is normal
[tex]A^TA=AA^T[/tex]
then A and A^T have the same nullspace (kernel). And
[tex]||Ax||=||A^Tx||[/tex]
Thank you.
can you help me with the proof? If A is normal
[tex]A^TA=AA^T[/tex]
then A and A^T have the same nullspace (kernel). And
[tex]||Ax||=||A^Tx||[/tex]
Thank you.