Proof That f(x) is 0 if Both Odd and Even

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If a function f(x) is both odd and even, it must be the constant function 0. An odd function is defined by f(-x) = -f(x), while an even function is defined by f(-x) = f(x). When a function satisfies both definitions, it leads to the equation f(-x) = -f(-x), which implies f(x) must equal 0. The discussion emphasizes the importance of correctly applying these definitions to reach the conclusion. Thus, no other function besides 0 can be both odd and even.
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Homework Statement


Prove that if f(x) is both odd and even (functions) then f(x) must be the constant function 0. Basically prove that no other function other than 0, can be both odd and even.
 
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How do you define an odd function and an even function?
 
neutrino said:
How do you define an odd function and an even function?


Odd function is when f(-x) = -f(x) and even is if f(-x) = f(-x)
 
STAR3URY said:
even is if f(-x) = f(-x)

That's not quite right.

But in a way, that is what you have to use once you have the definitions of both types of functions. :)
 
As neutrino said, you got the definition wrong. Get the definition right, and then you can make progress.
 
f(-x) = f(x) is even

f(-x) = -f(x) is odd
 
The definitions are correct. Now if a function has to fullfill both of these, it fullfills the product. Use this together with the fact that a square is always... and the fact that something is positive and negative at the same time must be...
 
Basically f(-x) = -f(-x) i.e. f = -f. The rest is algebra.
 
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